A potential divider consisting of two resistors in series with a supply voltage
a) Find VOUT:
VOUT = | VIN × R2 | = | 60 × 4 | = 24 V |
R2 + R1 | 4 + 6 |
b) Find VOUT:
VOUT = | VIN × R2 | = | 20 × 5 | = 10 V |
R2 + R1 | 5 + 5 |
c) Find VIN:
VIN = VOUT × | R2 + R1 | = 10 × | 5 + 10 | = 30 V |
R2 | 5 |
d) Find R2:
R2 | = | VOUT |
R2 + R1 | VIN |
R2 × VIN = (R2 + R1) × VOUT
R2 × 50 = R2 × 10 + 100
R2 × 40 = 100
R2 = 100 ÷ 40 = 2.5 Ω
e) Find R1:
R2 | = | VOUT |
R2 + R1 | VIN |
R2 × VIN = (R2 + R1) × VOUT
80 = 20 + R1 × 5
R1 × 5 = 60
R1 = 60 ÷ 5 = 12 Ω